Specific Heat Capacity of Solid by Method of Mixture | Physics Grade XI

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Specific Heat Capacity of Solid by Method of Mixture | Physics Grade XI

Specific Heat Capacity of Solid by the Method of Mixture

Specific Heat Capacity of Solid by the Method of Mixture
A calorimeter and stirrer are weighted and half of its volume is filled with water. Then it is again weighted to know the mass of water. The calorimeter is then placed inside the wooden box by surrounding the calorimeter with woolen clothes to prevent heat loss. The temperature of the calorimeter and its content are noted by the thermometer inserted into it. When the solid gains a constant temperature in the steam chamber, the calorimeter is brought below the chamber, its lid is opened and hot solid is put carefully in the calorimeter. The mixture is then stirred gently until the temperature of the mixture reaches a constant value.

To remove heat loss or gain, some wool or cotton clothes are kept in between calorimeter and the jacket. Here the mass of calorimeter with a stirrer, the mass of water, and initial temperature is noted. As the thermometer T1 shows constant temperature, the solid is transferred to the calorimeter and the final common temperature of the mixture is noted.

Mass of solid = m1
Mass of calorimeter and stirrer = m2
Mass of water = m3
Initial temperature of solid = θ1
Initial temperature of water and calorimeter = θ2
Final temperature of the mixture = θ3
Specific heat capacity of solid = s1 (let)
Specific heat capacity of thermometer = s2
Specific heat capacity of water = s3
 
The heat lost by solid = m1 s11 – θ3)
Similarly, heat gained by calorimeter = m2s23 – θ2), and heat gained by water = m3s33 – θ2)
 
From the principle of calorimetry,
         Heat lost by solid = heat gained by calorimeter and water
       or, m1 s11 – θ3) = m2s23 – θ2) + m3s33 – θ2)
       or, m1 s11 – θ3) = (θ3 – θ2) (m2s2 + m3s3)
                          or, s1 = [(θ3 – θ2) (m2s2 + m3s3)]/[m1– θ3)]

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