**Question: Obtain an expression for electric field due to an electric dipole at a point equidistant from each charge.**

**Ans:**Let us consider a dipole of charges +q and -q, separated by a distance r. we have to find out the electric field intensity at a point R at equidistance r from P and Q, i.e. to charges. The electric field intensity at point R due to charge +q is given by

E

_{1}= 1/4πϵ_{0}(q/r^{2}), directed along RUSimilarly, electric field intensity at a point R due to a charge -q at Q is given by E

_{2}in both, magnitude and direction as,E

_{2}= (q/r^{2}), directed along RSThe resultant intensity E in both magnitude and direction is given by diagonal RT of parallelogram RSTU. The resultant intensity id calculated by

E = √ (E

_{1}^{2}+ 2E_{1}E_{2}cosθ+ E_{2}^{2})And direction is given as

Β = tan

^{-1}[E_{1}sinθ/(E_{2}+ E_{1}cosθ)]
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